三角恒等变换公式

时间:2025-02-15 11:20:48 单机游戏

三角恒等变换公式包括:

两角和与差的三角函数和(差)角公式

$\sin(\alpha + \beta) = \sin\alpha\cos\beta + \cos\alpha\sin\beta$

$\sin(\alpha - \beta) = \sin\alpha\cos\beta - \cos\alpha\sin\beta$

$\cos(\alpha + \beta) = \cos\alpha\cos\beta - \sin\alpha\sin\beta$

$\cos(\alpha - \beta) = \cos\alpha\cos\beta + \sin\alpha\sin\beta$

$\tan(\alpha + \beta) = \frac{\tan\alpha + \tan\beta}{1 - \tan\alpha\tan\beta}$

$\tan(\alpha - \beta) = \frac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}$

二倍角公式

$\sin(2\alpha) = 2\sin\alpha\cos\alpha$

$\cos(2\alpha) = \cos^2\alpha - \sin^2\alpha = 2\cos^2\alpha - 1 = 1 - 2\sin^2\alpha$

$\tan(2\alpha) = \frac{2\tan\alpha}{1 - \tan^2\alpha}$

三倍角公式

$\sin(3\alpha) = 3\sin\alpha - 4\sin^3\alpha$

$\cos(3\alpha) = 4\cos^3\alpha - 3\cos\alpha$

半角公式

$\sin^2\left(\frac{\alpha}{2}\right) = \frac{1 - \cos\alpha}{2}$

$\cos^2\left(\frac{\alpha}{2}\right) = \frac{1 + \cos\alpha}{2}$

$\tan^2\left(\frac{\alpha}{2}\right) = \frac{1 - \cos\alpha}{1 + \cos\alpha}$

$\tan\left(\frac{\alpha}{2}\right) = \frac{\sin\alpha}{1 + \cos\alpha} = \frac{1 - \cos\alpha}{\sin\alpha}$

万能公式与半角公式

$\sin\alpha = \frac{2\tan\left(\frac{\alpha}{2}\right)}{1 + \tan^2\left(\frac{\alpha}{2}\right)}$

$\cos\alpha = \frac{1 - \tan^2\left(\frac{\alpha}{2}\right)}{1 + \tan^2\left(\frac{\alpha}{2}\right)}$

$\tan\alpha = \frac{2\tan\left(\frac{\alpha}{2}\right)}{1 - \tan^2\left(\frac{\alpha}{2}\right)}$

积化和差公式

$\sin\alpha \cdot \cos\beta = \frac{1}{2}[\sin(\alpha + \beta) + \sin(\alpha - \beta)]$

$\cos\alpha \cdot \sin\beta = \frac{1}{2}[\sin(\alpha + \beta) - \sin(\alpha - \beta)]$

$\cos\alpha \cdot \cos\beta = \frac{1}{2}[\cos(\alpha + \beta) + \cos(\alpha - \beta)]$

$\sin\alpha \cdot \sin\beta = -\frac{1}{2}[\cos(\alpha + \beta) - \cos(\alpha - \beta)]$

这些公式在解三角函数方程、简化三角函数表达式以及进行三角函数的积分和微分等计算中起到重要的作用。