要用数组编写发牌程序,可以按照以下步骤进行:
定义牌组:
创建一个二维数组来表示一副牌,其中每个元素包含花色和牌面信息。
洗牌:
使用随机数生成器打乱牌的顺序。
发牌:
按照一定的规则将洗好的牌分发给每个玩家。
下面是一个用C语言编写的简单示例代码:
```c
include include include define NUM_SUITS 4 define NUM_CARDS_PER_SUIT 13 // 定义花色和牌面 const char *suits[] = {"Hearts", "Diamonds", "Clubs", "Spades"}; const char *card_names[] = {"2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A"}; // 初始化牌组 char deck[NUM_SUITS][NUM_CARDS_PER_SUIT]; int deck_used[NUM_SUITS][NUM_CARDS_PER_SUIT] = {0}; // 洗牌函数 void shuffle() { srand(time(NULL)); for (int i = NUM_SUITS - 1; i > 0; i--) { int j = rand() % (i + 1); char temp = deck[i][j]; deck[i][j] = deck[j][i]; deck[j][i] = temp; } } // 发牌函数 void deal_cards(char players[NUM_CARDS_PER_SUIT]) { int num_players = 4; int cards_per_player = NUM_CARDS_PER_SUIT / num_players; int remaining_cards = NUM_CARDS_PER_SUIT; for (int player = 0; player < num_players; player++) { for (int i = 0; i < cards_per_player; i++) { int card_index = rand() % remaining_cards; while (deck_used[card_index / NUM_CARDS_PER_SUIT][card_index % NUM_CARDS_PER_SUIT] != 0) { card_index = rand() % remaining_cards; } players[player][i] = deck[card_index / NUM_CARDS_PER_SUIT][card_index % NUM_CARDS_PER_SUIT]; deck_used[card_index / NUM_CARDS_PER_SUIT][card_index % NUM_CARDS_PER_SUIT] = 1; remaining_cards--; } } } int main() { // 初始化牌组 for (int suit = 0; suit < NUM_SUITS; suit++) { for (int card = 0; card < NUM_CARDS_PER_SUIT; card++) { deck[suit][card] = card_names[card] + suits[suit]; } } // 洗牌 shuffle(); // 发牌 char players[NUM_CARDS_PER_SUIT]; deal_cards(players); // 输出每个玩家的牌 for (int player = 0; player < num_players; player++) { printf("Player %d:\n", player + 1); for (int card = 0; card < NUM_CARDS_PER_SUIT; card++) { printf("%s ", players[player][card]); } printf("\n"); } return 0; } ``` 代码解释: 使用两个字符串数组分别表示花色和牌面。 创建一个二维字符数组`deck`来存储所有牌,并使用一个二维整数数组`deck_used`来标记每张牌是否已经发出。 使用Fisher-Yates洗牌算法打乱牌的顺序。 将洗好的牌分发给每个玩家,确保每张牌只发一次。 初始化牌组,调用洗牌和发牌函数,并输出每个玩家的牌。 这个示例代码展示了如何使用数组来模拟一副扑克牌,并进行定义花色和牌面:
初始化牌组:
洗牌函数:
发牌函数:
主函数: